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## JavaScript Challenge Internship to CEO #14

Print the first 10 Fibonacci numbers without recursion.

Fibonacci series: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …

## Explanation

We start with the creation of the for loop. We have to define the loop is running from 2 to 10 in order to get the first 10 numbers. We start with the 0 and the 1 and need 8 more.

Any number n of the Fibonacci series is created by adding up the number n-1 with the number n-2.

To get the third number, we need to have number n-1 and n-2. With n = 3, this will be number 2 and 1 of the series.

The equation is therefore:

n = n – 1 + n – 2;

Result into:

2 = 1 + 0; The 3rd number of the Fibonacci series.

Then we need to switch the n – 1 and n – 2 to the newly created ones to go further in our Fibonacci series. E voilá, do it as long as you want to get all numbers for the Fibonacci series.

The complete outcome of the console:

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## JavaScript Challenge Internship to CEO #13

Find the maximum number in an array of numbers.

The array: [-21, 113, -34, 1, -9, 5, 99, 1, 0].

## Explanation

To accomplish our task, we create a function called `findMax()` and pass in our array.

Inside the body, we need to create a variable referencing our found maximum value. We set the variable `max` to the first element of our array. Since this it the first maximum existing. We didn’t check any other so far.

The next step is to loop over the array and check if the element we are currently looking at is greater than our current max value.

If so, replace it to the newly found maximum element of `array`.

Once, we are done with iterating, comparing, and adding, just return the found maximum and print it to the console, and you are done!

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