Print a multiplication table with 6 with `for-loop` .

Expected result:

## Explanation

The row of six goes from 6 to 60. Therefore we need a `for-loop `that iterates 10 times. You are a bit familiar with loops now (since you made challenge #01 and #02) and you know the rules of a` for-loop`.

The variable `row` is our printed statement every iteration. To get the multiplication table of six, we just multiply the base number of 6 with the next value of the iteration process. The row of six starts with 6*1, then 6*2, and then 6*3, and so on…

To print now a decent table, we have to display the entire entry as a term. So `6 * 1 = 6` as code is `"6 * " + i + " = " 6 * i` We need to have the quotation marks here, because we want a string as result. If we don’t use the quotation marks the “compiler” would then complain about the `=` . Leaving out also the = and the `+` sign in front of it would result in the following line:

``let row = 6 *  + i + 6 * i;``

Running the program then will print this: